优化转存结果的查询逻辑和回显

This commit is contained in:
Cp0204 2024-04-14 01:08:07 +08:00
parent da35ebfa33
commit d49b7a6f18

View File

@ -11,6 +11,7 @@ import os
import re
import sys
import json
import time
import random
import requests
from datetime import datetime
@ -533,22 +534,37 @@ class Quark:
return False
def query_task(self, task_id):
url = "https://drive-m.quark.cn/1/clouddrive/task"
querystring = {
"pr": "ucpro",
"fr": "pc",
"uc_param_str": "",
"task_id": task_id,
"retry_index": "1",
"__dt": int(random.uniform(1, 5) * 60 * 1000),
"__t": datetime.now().timestamp(),
}
headers = self.common_headers()
response = requests.request(
"GET", url, headers=headers, params=querystring
).json()
if response["code"] == 32003:
response["message"] = "容量超限"
retry_index = 0
while True:
url = "https://drive-m.quark.cn/1/clouddrive/task"
querystring = {
"pr": "ucpro",
"fr": "pc",
"uc_param_str": "",
"task_id": task_id,
"retry_index": retry_index,
"__dt": int(random.uniform(1, 5) * 60 * 1000),
"__t": datetime.now().timestamp(),
}
headers = self.common_headers()
response = requests.request(
"GET", url, headers=headers, params=querystring
).json()
if response["data"]["status"] != 0:
if retry_index > 0:
print()
break
else:
if retry_index == 0:
print(
f"正在等待[{response['data']['task_title']}]执行结果",
end="",
flush=True,
)
else:
print(".", end="", flush=True)
retry_index += 1
time.sleep(0.500)
return response
def do_rename_task(self, task):