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修复某些情况下顺序命名预览界面显示的重命名与实际操作不一致的问题
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x1ao4
parent
6935c609b4
commit
d6390cde99
174
app/run.py
174
app/run.py
@ -331,56 +331,154 @@ def get_share_detail():
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if file["dir"]: # 跳过文件夹
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return float('inf')
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file_name = file["file_name"]
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filename = file["file_name"]
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# 1. 首先尝试提取SxxExx格式（如S01E01）
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match_s_e = re.search(r'[Ss](\d+)[Ee](\d+)', file_name)
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# 提取文件名，不含扩展名
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file_name_without_ext = os.path.splitext(filename)[0]
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# 1. "第X期/集/话" 格式 - 保持最高优先级
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match_chinese = re.search(r'第(\d+)[期集话]', filename)
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episode_num = int(match_chinese.group(1)) if match_chinese else 0
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# 5. 文件名含"上中下"（优先处理，因为可能与其他格式同时存在）
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if match_chinese:
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# 如果同时存在集数和上中下，则按照集数*10+位置排序
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if '上' in filename:
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return episode_num * 10 + 1
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elif '中' in filename:
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return episode_num * 10 + 2
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elif '下' in filename:
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return episode_num * 10 + 3
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return episode_num * 10
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elif '上' in filename:
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return 1
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elif '中' in filename:
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return 2
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elif '下' in filename:
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return 3
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# 1.2 "X集/期/话" 格式 - 与我们修改后的优先级一致
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match_chinese_simple = re.search(r'(\d+)[期集话]', filename)
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if match_chinese_simple:
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return int(match_chinese_simple.group(1))
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# 2.1 S01E01 格式，提取季数和集数
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match_s_e = re.search(r'[Ss](\d+)[Ee](\d+)', filename)
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if match_s_e:
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season = int(match_s_e.group(1))
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episode = int(match_s_e.group(2))
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return season * 1000 + episode
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# 2. 尝试提取E01/EP01格式
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match_e = re.search(r'[Ee][Pp]?(\d+)', file_name)
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# 2.2 E01/EP01 格式，仅提取集数
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match_e = re.search(r'[Ee][Pp]?(\d+)', filename)
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if match_e:
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return int(match_e.group(1))
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# 3. 首先尝试提取期数（第X期）
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period_match = re.search(r'第(\d+)期[上中下]', file_name)
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if period_match:
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period_num = int(period_match.group(1))
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# 根据上中下调整排序
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if '上' in file_name:
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return period_num * 3 - 2
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elif '中' in file_name:
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return period_num * 3 - 1
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elif '下' in file_name:
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return period_num * 3
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return period_num * 3
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# 2.3 1x01 格式，提取季数和集数
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match_x = re.search(r'(\d+)[Xx](\d+)', filename)
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if match_x:
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season = int(match_x.group(1))
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episode = int(match_x.group(2))
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return season * 1000 + episode
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# 4. 尝试提取日期格式（YYYY-MM-DD）
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date_match = re.search(r'(\d{4})-(\d{2})-(\d{2})', file_name)
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if date_match:
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year = int(date_match.group(1))
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month = int(date_match.group(2))
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day = int(date_match.group(3))
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base_value = year * 10000 + month * 100 + day
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# 如果同一天有多个文件，根据"上中下"或其他标识符进行排序
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if '上' in file_name:
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return base_value * 10 + 1
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elif '中' in file_name:
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return base_value * 10 + 2
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elif '下' in file_name:
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return base_value * 10 + 3
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return base_value * 10
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# 2.4 数字后接4K格式
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match_4k = re.search(r'(\d+)[-_\s]*4[Kk]', filename)
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if match_4k:
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return int(match_4k.group(1))
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# 5. 尝试提取任何数字
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number_match = re.search(r'(\d+)', file_name)
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if number_match:
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return int(number_match.group(1))
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# 2.5 方括号包围的数字
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match_bracket = re.search(r'\[(\d+)\]', filename)
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if match_bracket:
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return int(match_bracket.group(1))
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# 6. 默认使用原文件名
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return float('inf')
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# 2.6 中括号包围的数字
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match_cn_bracket = re.search(r'【(\d+)】', filename)
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if match_cn_bracket:
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return int(match_cn_bracket.group(1))
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# 2.7 下划线包围的数字
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match_underscore = re.search(r'_?(\d+)_', filename)
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if match_underscore:
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return int(match_underscore.group(1))
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# 3. 日期格式识别（支持多种格式）
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# 3.1 完整的YYYYMMDD格式
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match_date_compact = re.search(r'(20\d{2})(\d{2})(\d{2})', filename)
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if match_date_compact:
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year = int(match_date_compact.group(1))
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month = int(match_date_compact.group(2))
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day = int(match_date_compact.group(3))
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return year * 10000 + month * 100 + day
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# 3.2 YYYY-MM-DD 或 YYYY.MM.DD 或 YYYY/MM/DD 格式
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match_date_full = re.search(r'(20\d{2})[-./](\d{1,2})[-./](\d{1,2})', filename)
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if match_date_full:
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year = int(match_date_full.group(1))
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month = int(match_date_full.group(2))
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day = int(match_date_full.group(3))
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return year * 10000 + month * 100 + day
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# 3.3 MM/DD/YYYY 或 DD/MM/YYYY 格式
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match_date_alt = re.search(r'(\d{1,2})[-./](\d{1,2})[-./](20\d{2})', filename)
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if match_date_alt:
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# 假设第一个是月，第二个是日（美式日期）
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month = int(match_date_alt.group(1))
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day = int(match_date_alt.group(2))
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year = int(match_date_alt.group(3))
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# 检查月份值，如果大于12可能是欧式日期格式（DD/MM/YYYY）
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if month > 12:
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month, day = day, month
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return year * 10000 + month * 100 + day
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# 3.4 MM/DD 格式（无年份），假设为当前年
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match_date_short = re.search(r'(\d{1,2})[-./](\d{1,2})', filename)
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if match_date_short:
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# 假设第一个是月，第二个是日
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month = int(match_date_short.group(1))
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day = int(match_date_short.group(2))
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# 检查月份值，如果大于12可能是欧式日期格式（DD/MM）
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if month > 12:
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month, day = day, month
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# 由于没有年份，使用一个较低的基数，确保任何有年份的日期都排在后面
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return month * 100 + day
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# 3.5 年期格式，如"2025年14期"
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match_year_issue = re.search(r'(20\d{2})[年].*?(\d+)[期]', filename)
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if match_year_issue:
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year = int(match_year_issue.group(1))
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issue = int(match_year_issue.group(2))
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return year * 1000 + issue
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# 3.6 日期+期数的复合格式，例如：2025-04-18 第5期上
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match_date_episode = re.search(r'(20\d{2})[-./](\d{1,2})[-./](\d{1,2}).*?第(\d+)[期集话]', filename)
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if match_date_episode:
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year = int(match_date_episode.group(1))
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month = int(match_date_episode.group(2))
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day = int(match_date_episode.group(3))
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episode = int(match_date_episode.group(4))
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date_val = year * 10000 + month * 100 + day
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# 将日期值作为主排序，期数为次要排序
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if '上' in filename:
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return date_val * 100 + episode * 10 + 1
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elif '中' in filename:
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return date_val * 100 + episode * 10 + 2
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elif '下' in filename:
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return date_val * 100 + episode * 10 + 3
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return date_val * 100 + episode * 10
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# 4. 纯数字格式（文件名开头是纯数字）
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match_num = re.match(r'^(\d+)', file_name_without_ext)
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if match_num:
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return int(match_num.group(1))
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# 5. 尝试匹配文件名中的任何数字
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any_num_match = re.search(r'(\d+)', filename)
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if any_num_match:
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return int(any_num_match.group(1))
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# 6. 默认使用更新时间
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return file.get("created_at", file.get("updated_at", file.get("last_update_at", 0)))
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# 过滤出非目录文件，并且排除已经符合命名规则的文件
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files_to_process = []
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